Let A and B are two independent events. The probability that both A and B happen is \(\frac{1}{12}\) and probability that neither A nor B happen is \(\frac{1}{2}\) Then

1
\(\rm P(A)=\frac{1}{3}, P(B)=\frac{1}{4}\)
2
\(\rm P(A)=\frac{1}{2}, P(B)=\frac{1}{6}\)
3
\(\rm P(A)=\frac{1}{6}, P(B)=\frac{1}{2}\)
4
\(\rm P(A)=\frac{2}{3}, P(B)=\frac{1}{8}\)

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