IfΒ \(\frac{d y}{d x}+\left(\frac{x}{1+x^{2}}\right) y=\frac{\sqrt{x}}{\sqrt{1+x^{2}}} ; y(0)=0\),Β then 𝑦(1) will be

1
\(\frac{2}{{3}}\)
2
\(\frac{2}{\sqrt{3}}\)
3
\(\frac{\sqrt{2}}{3}\)
4
\(\sqrt{\frac{2}{3}}\)

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