When photons of energy \(\dfrac{hc}{\lambda}\) fall on a metal surface, photoelectrons are ejected from it. If the work function of the surface is \(hv_0\), then
1
Maximum kinetic energy of the electron is \(\left(\dfrac{hc}{\lambda}\right) - hv_0\)
2
Maximum kinetic energy of the photoelectron is equal to \(\dfrac{hc}{\lambda}\)
3
Minimum KE of the photoelectron is zero
4
Minimum kinetic energy of the photoelectron is equal to \(\dfrac{hc}{\lambda}\)