If \(12\) distinct balls are to be placed in \(3\) identical boxes, then the probability that one of the boxes contains exactly \(3\) balls is
1
\(\dfrac {55}{3}\left ( \dfrac {2}{3} \right )^{11}\)
2
\(55\left ( \dfrac {2}{3} \right )^{11}\)
3
\(22\left ( \dfrac {1}{3} \right )^{11}\)
4
\(228\left ( \dfrac {2}{3} \right )^{12}\)