If \(x\) follows the Binomial distribution with parameters \(n=6\) and \(p\) and \(9P(X=4) = P(X=2)\), then \(p\) is

1
\(\dfrac {1}{4}\)
2
\(\dfrac {1}{3}\)
3
\(\dfrac {1}{2}\)
4
\(\dfrac {2}{3}\)

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