The equation of a circle which has a tangent \(3x+4y=6\) and two normals given by \((x-1)(y-2)=0\) is

1
\((x-3)^2+(y-4)^2=5^2\)
2
\(x^2+y^2-4x-2y+4=0\)
3
\(x^2+y^2-2x-4y+4=0\)
4
\(x^2+y^2-2x-4y+5=0\)

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