CUET and UG exam JEE Main Mock Test Series 2025 Mathematics Differential Calculus Applications of Derivatives
Let the sum of the maximum and the minimum values of the function \(f(x) = \frac{2x^2 - 3x + 8}{2x^2 + 3x + 8}\) be \(\frac{m}{n}\), where gcd(m, n) = 1. Then m + n is equal to :
1
182
2
217
3
195
4
201