If x = at4 and y = 2at2, then \(\frac{\mathrm{d}^2 y}{\mathrm{~d} x^2}\) is equal to:

1
\(-\frac{1}{4 a t^4}\)
2
\(-\frac{2}{t^3}\)
3
\(-\frac{1}{t}\)
4
\(-\frac{1}{2 a t^6}\)

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