A circuit element 'X' when connected to peak voltage of 200 V, a peak current of 5A flows which lags behind the voltage by \(\frac{\pi}{2}\). A circuit element Y when connected to same peak voltage, same peak current flows which is in phase with the voltage. Now X and Y are connected in series with same peak voltage. The rms value of current through the circuit will be:
1
5 A
2
\(\rm \frac{5}{\sqrt2}A\)
3
2.5 A
4
5√2 A