If \(\int \frac{\sin x}{3+4 \cos ^2 x} \mathrm{~d} x\) = \(\mathrm{A}{\tan ^{-1}(\mathrm{~B} \cos x)+\mathrm{c}}\), (where c is a constant of integration), then the value of A + B is
1
\(\frac{5}{2 \sqrt{3}}\)
2
\(\frac{-1}{2 \sqrt{3}}\)
3
\(\frac{-2}{\sqrt{3}}\)
4
\(\frac{\sqrt{3}}{2}\)