Three numbers are chosen at random without replacement from \(\{1, 2, 3, \ldots,8\}\). The probability that their minimum is \(3\), given that their maximum is \(6\), is:
1
\(\displaystyle \frac{3}{8}\)
2
\(\displaystyle \frac{1}{5}\)
3
\(\displaystyle \frac{1}{4}\)
4
\(\displaystyle \frac{2}{5}\)