CUET and UG exam CUET UG 2025 Mock Test Series Mathematics Trigonometry Inverse Trigonometric Functions
If α > β > γ > 0, then the expression
\(\cot ^{-1}\left\{\beta+\frac{\left(1+\beta^{2}\right)}{(\alpha-\beta)}\right\}+\cot ^{-1}\left\{\gamma+\frac{\left(1+\gamma^{2}\right)}{(\beta-\gamma)}\right\}\) + \(\cot ^{-1}\left\{\alpha+\frac{\left(1+\alpha^{2}\right)}{(\gamma-\alpha)}\right\}\) is equal to:
1
\(\frac{\pi}{2}-(\alpha+\beta+\gamma)\)
2
3 π
3
0
4
π