If y = f(x), \(p=\frac{d y}{d x} ; q=\frac{d^{2} y}{d x^{2}}\) then \(\frac{d^{2} x}{d y^{2}}\) is equal to

1
\(-\frac{q}{p^{2}}\)
2
\(\frac{q}{p}\)
3
\(-\frac{q}{p^{3}}\)
4
\(\frac{q}{p^{2}}\)

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