Answer using the follwing data and find out the most stable ion in its reduced form.
EoCl2/Cl- = 1.36V
EoCr3+ /Cr=- 0.74V
EoCrO72-/Cr3+ = 1.33V
EoMnO4- /Mn2+ = 1.51V
1
Cl–
2
Cr3+
3
Cr
4
Mn2+
EoCl2/Cl- = 1.36V
EoCr3+ /Cr=- 0.74V
EoCrO72-/Cr3+ = 1.33V
EoMnO4- /Mn2+ = 1.51V