If \(\frac{{3\; - \;7x}}{x} + \frac{{3\; - \;4y}}{y} + \frac{{3\; + \;11z}}{z} = \frac{6}{\alpha }\) and the value of \(\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = \frac{\alpha }{2}\;\) then the value of α is

1
± 1
2
± 2
3
± 6
4
± 3

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