The following function computes the maximum value contained in an integer array p[ ] of size n (n >= 1).

int max(int*p,intn) {

int a=0,b=n-1;

while (__________) {

if (p[a]<=p[b])  

{a=a+1;}

else                       

{b=b-1;}

}

return p[a];

}

The missing loop condition is

1
a ! = n
2
b ! = 0
3
b > (a+1)
4
b ! = a

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