The least possible value of k ,
for which the following boundary value problem has a solution is:
\(y''(t) + 3y'(t) + ky(t) = 0, \quad t \in \mathbb{R}, \)
with the boundary conditions:
\(y(0) = 0, \quad y(2) = 0, \quad y\left(\frac{1}{2}\right) = 2 \).
Find the value of k ( accurate up to two decimal places)
Enter numerical value using the virtual keypad. Round off where necessary.