Considering the following reaction :

\({ }^{238} \mathrm{U}_{92}+{ }^4 \mathrm{He}_2 \longrightarrow{ }^{\mathrm{M}} \mathrm{X}_{\mathrm{A}}+{ }^1 \mathrm{n}_0\)

number of neutrons present in nucleus of X are __________.

1
147
2
238
3
94
4
162

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