Match List-I with List-II
|
List-I Series |
List-II Radius of convergence |
||
|
(A) |
\(\sum\left(\frac{i z-1}{2+i}\right)^n\) |
(I) |
0 |
|
(B) |
\(\sum\left(2^{-1} z^2\right)^n\) |
(II) |
√5 |
|
(C) |
\(\sum(n+2 i)^n z^n\) |
(III) |
1 |
|
(D) |
\(\sum\left(1+\frac{1}{n}\right)^n z^n\) |
(IV) |
√2 |
Choose the correct answer from the options given below:
1
(A) - (I), (B) - (II), (C) - (III), (D) - (IV)
2
(A) - (I), (B) - (III), (C) - (II), (D) - (IV)
3
(A) - (II), (B) - (IV), (C) - (I), (D) - (III)
4
(A) - (III), (B) - (IV), (C) - (I), (D) - (II)