The difference in the Coulomb energy between the mirror nuclei 4924Cr and 4925Mn is 6.0 MeV. Assuming the nuclei have a spherically symmetric charge distribution and that \(e^2 \approx 1.0 \, \text{MeV-fm}\) , calculate the radius of the 4925Mn nucleus.
1
\( 4.9 \times 10^{-13} \, \text{m}\)
2
\(4.9 \times 10^{-15} \, \text{m}\)
3
\(5.1 \times 10^{-13} \, \text{m}\)
4
\(5.1 \times 10^{-15} \, \text{m}\)