The function f(x) = 8 loge x - x2 + 3 attains its global minimum over the interval [1, e] at x = ________.
(Here loge x is the natural logarithm of x and e2 = 7.39)
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\(\frac{1+e}{2}\)
The function f(x) = 8 loge x - x2 + 3 attains its global minimum over the interval [1, e] at x = ________.
(Here loge x is the natural logarithm of x and e2 = 7.39)