Let biased coin be tossed 5 times. If the probability of getting 4 heads is equal to the probability of getting 5 heads, then the probability of getting at most two heads is :
1
\(\frac{275}{6^5}\)
2
\(\frac{36}{5^4}\)
3
\(\frac{181}{5^5}\)
4
\(\frac{46}{6^4}\)