A particle is projected at time t = 0 from a point P with a speed v0 at an angle of 45° to the horizontal. Find the magnitude and the direction of the angular momentum
of the particle about the point P at time t = v0/g.
1
\(\frac{mv_0^3}{\sqrt 2 g} \) , in the negative z-direction
2
\(\frac{mv_0^3}{2 \sqrt 2 g} \), in the positive z-direction
3
\(\frac{mv_0^3}{2 \sqrt 2 g} \), in the negative z-direction
4
None