In ΔABC, D and E are the points on the sides AB and AC, respectively such that ∠AED = ∠ABC. If AE = 6 cm, BD = 2 cm, DE = 3 cm and BC = 5 cm, then (AB + AC) is equal to:

1
\(\frac{86}{3}\) cm
2
\(\frac{70}{3}\) cm
3
\(\frac{50}{3}\) cm
4
\(\frac{49}{3}\) cm

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