A particle executes linear simple harmonic motion with an amplitude of 3 cm. When the particle is at 2 cm from the mean position, the magnitude of its velocity is equal to that of its acceleration. Then its time period in seconds is
1
\(\frac{2 \pi}{\sqrt{3}}\)
2
\(\frac{\sqrt{5}}{\pi}\)
3
\(\frac{\sqrt{5}}{2 \pi}\)
4
\(\frac{4 \pi}{\sqrt{5}}\)