In the following question, two equations numbered I and II are given. You have to solve both the equations and give the answer

I. \(x + \frac{1}{x} = \frac{{50}}{7}\)

II. 4y2 + 4 + 17y = 0

1
x < y
2
x > y
3
x = y OR the relationship cannot be determined
4
x ≥ y
5
x ≤ y

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