A ball is projected with initial velocity v0 such that maximum height of the projectile obtained is \(\frac {1}{3}^{\rm rd}\)  the value of its horizontal range. The value of horizontal range is-

1
\(\frac {24}{25} \frac {v_{0}^{2}}{g}\)
2
\(\frac {25}{4} \frac {v_{0}^{2}}{g}\)
3
\(\frac {25}{24} \frac {v_{0}^{2}}{g}\)
4
\(\frac {4}{25} \frac {v_{0}^{2}}{g}\)

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