state gov DSSSB Patwari Mock Test Mathematics Integral Calculus Indefinite Integrals

\(\int {\frac{{{x^3}dx}}{{1 + {x^8}}}} = \)

1
4 tan-1 x3 + c
2
\(\frac{1}{4}{\tan ^{ - 1}}{x^4} + c\)
3
x + 4 tan-1 x4 + c
4
\({x^2}\frac{1}{4}{\tan ^{ - 1}}{x^4} + c\)
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