Solve the given equations and answer the following question.

I. 3x² - (4p  + 19)x + 368 = 0

II. y² + Qy + 13p = 0

III.z² + (p + Q)z + (10Q + 30)

Note:

i) 2p = Q

ii) One of the roots in equation I is = (25% of 320 - 6² + (3 × 7) - 49)

iii) Value of R = -1 × (Higher root in the equation III)

 A container consisting of milk and water are in the ratio (p + 3): (Q - 2) and the total quantity of mixture in the container is 5R, if 2R litres of mixture is removed and ‘S’litres of milk is added then the ratio becomes 1: 1. Find the value of S.