If 45a + 120b + 150c is the linear combination represents the H.C.F of 45, 120 and 150, then find the possible value of a, b and c.

1
a = 1, b = 1, c = 1
2
a = -1, b = 1, c = 1
3
a = 1, b = -1, c = 1
4
a = 1, b = 1, c = -1

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