If\(sec\theta = { \sqrt{a^2+b^2} \over a}\) then the value of cotθ is:

1
\( { \sqrt{a^2-b^2} \over a^2}\)
2
\( {a^2} \over \sqrt{a^2+b^2}\)
3
\(x = {\sqrt{a^2+b^2} \over b}\)
4
\({a \over b}\)

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