Between 10 O'clock and 11 O'clock, when the times at which the minutes and hour hands be at 66° with each other are 10 hours t1, min. and 10 hours t2 min., then t1 + t2 =
1
\(\frac{{200}}{11} \)
2
\(\frac{{900}}{11} \)
3
\(\frac{{1300}}{11} \)
4
\(\frac{{1200}}{11} \)