In the given figure; if radius of the circle is 21 cm and ∠POQ is 120°, then area of segment PRQ in (cm)2 is :
1
\(\frac{21}{2}\)(44 − 21\(\sqrt{3}\))
2
\(\frac{21}{4}\)(88 − 21\(\sqrt{3}\))
3
\(\frac{21}{4}\)(88\(\sqrt{3}\) − 21)
4
\(\frac{21}{4}\)(88\(\sqrt{2}\) − 21)