The solution for x of the equation \(\frac{{x + a}}{{b + c}} + \frac{{x + b}}{{a + c}} + \frac{{x + c}}{{a + b}} = \; - 3\) given \(\frac{1}{{b + c}} + \frac{1}{{a + c}} + \frac{1}{{a + b}} \ne 0\), is

1
a + b + c
2
-(a + b + c)
3
0
4
1

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