If \(\rm\left(\frac{2}{x}-\frac{3}{y}\right)=a\) and \(\rm xy=\frac{3}{b^2}\) then \(\rm\frac{4}{x^2}+\frac{9}{y^2}\) in terms of 'a' and 'b' is

1
a2 + 4b2
2
a2 + 6b2
3
\(\rm a^2+\frac{b^2}{4}\)
4
\(\rm a^2+\frac{24}{b^2}\)

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