If x is not equal to zero, then
\({\left( {\frac{{ - 8{x^3}}}{{27}}} \right)^{ - 1/3}} - {\left( {\frac{{8{x^3}}}{{27}}} \right)^{ - 1/3}} \) is equal to
1
0
2
\(\frac{-3}{2x}\)
3
\(\frac{-3}{x}\)
4
\(\frac{3}{x}\)
If x is not equal to zero, then
\({\left( {\frac{{ - 8{x^3}}}{{27}}} \right)^{ - 1/3}} - {\left( {\frac{{8{x^3}}}{{27}}} \right)^{ - 1/3}} \) is equal to