If sin2 θ - cos2 θ - 3 sin θ + 2 = 0, 0° < θ < 90°, then what is the value of \(\frac{1}{\sqrt{\sec\theta-\tan\theta}}\) is:

1
\(\sqrt[2]{3}\)
2
\(\sqrt[2]{2}\)
3
\(\sqrt[4]{3}\)
4
\(\sqrt[4]{2}\)

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