Given two quadratic equations,
I. x2 - 31x + 240 = 0
Equation I has two roots x1, x2. (x1 > x2)
II. 3y2 – 7y – 3 = 8y - 3y2 - 9
Equation II has two roots y1, y2. (y2 > y1)
Find the equation whose roots are (– 2y1 + x1), - (y2 – x2).
1
x2 - 28x - 195 = 0
2
x2 - 28x + 195 = 0
3
x2 + 28x - 195 = 0
4
x2 + 28x + 195 = 0
5
Cannot be determined