Solution of the equation \(\frac{{\left( {4 + a} \right)\left( {5 - a} \right)}}{{\left( {2 + a} \right)\left( {7 - a} \right)}} = 1\) is -

1
\(a = \frac{2}{3}\)
2
\(a = - \frac{2}{3}\)
3
\(a = \frac{3}{2}\)
4
\(a = - \frac{3}{2}\)

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