If V be the volume and S be the surface area of a cuboid of dimensions a, b, c, then \(\frac{1}{V}\)is equal to

1
\(2S(a + b+ 2c)\)
2
\(S(2a+2b+2c)\)
3
\(\frac{2}{S}\left(\frac{1}{a}+\frac{1}{b}+\frac{1}{c}\right)\)
4
\(S(a+2b+3c)\)
5
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