A solid hemisphere has radius 14 cm. It is melted to form a cylinder such that the ratio of its curved surface area and total surface area is 2 ∶ 3. What is the radius (in cm) of its base?

1
\(\frac{10}{\sqrt[3]{3}}\)
2
\(\frac{14}{\sqrt[3]{3}}\)
3
\(\frac{7}{\sqrt[3]{3}}\)
4
\(\frac{21}{\sqrt[3]{3}}\)

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