If \(\frac{a}{x}+\frac{b}{y}=m\) and \(\frac{b}{x}+\frac{a}{y}=n\), then \(\frac{y}{x}\) is equal to

1
\(\frac{ma+nb}{na+mb}\)
2
\(\frac{ma-nb}{na+mb}\)
3
\(\frac{ma-nb}{na-mb}\)
4
\(\frac{ma+nb}{na-nb}\)

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