If \(\frac{3\text{x+y}+2}{3}=\frac{3\text{x−y}−1}{2}=\frac{\text{x+3y}+1}{4}\), then find the value of x and y.

1
x = −2, y = \(\frac{−13}{5}\)
2
x = \(\frac{7}{8}\), y = −5
3
x = \(\frac{1}{3}\), y = \(\frac{3}{4}\)
4
x = 2, y = 3

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