Quantitative Aptitude Geometry Triangles, Congruence and Similarity

Let ΔABC ~ ΔPQR and \(\rm \frac{ar(\Delta ABC)}{ar (\Delta PQR)} = \frac{144}{49}\) If AB = 12 cm, BC = 7 cm and AC = 9 cm, then PR (in cm) is equal to:

1

12

2

\(\frac{49}{12}\)

3

\(\frac{108}{7}\)

4

\(\frac{21}{4}\)

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