The probability that a ticketless traveler is caught during a trip is 0.1 . If the traveler makes 4 trips, the probability that he/she will be caught during at least one of the trips is:
1
1 - (0.9)4
2
(1 - 0.9)4
3
1 -(1 - 0.9)4
4
(0.9)4
5
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