An object of mass 'm' is projected from origin in a vertical xy plane at an angle 45° with the x-axis with an initial velocity v0. The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [g is acceleration due to gravity]

1
\(\rm \frac{m v_{0}^{3}}{2 \sqrt{2} g}\) along negative z-axis
2
\(\rm \frac{m v_{0}^{3}}{2 \sqrt{2} g}\) along positive z-axis 
3
\(\rm \frac{m v_{0}^{3}}{4 \sqrt{2} g}\) along positive z-axis 
4
\(\rm \frac{m v_{0}^{3}}{4 \sqrt{2} g}\) along negative z-axis
5
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