If the derivative of the function \(f(x)=\left\{\begin{array}{cc} b x^2+a x+4 ; & x \geq-1 \\ a x^2+b ; & x<-1 \end{array}\right.\) is everywhere continuous, then

1
a = 2, b = 3
2
a = 3, b = 2
3
a = – 2, b = – 3
4
a = – 3, b = – 2
5
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