Consider a ray of light incident from air onto a slab of glass (refractive index n) of width d, at an angle θ. The phase difference between the ray reflected by the top surface of the glass and the bottom surface is

1
\(\rm \frac{4\pi d}{\lambda} \left(1-\frac{1}{n^2}\sin^2 \theta \right) ^{1/2}+\pi\)
2
\(\rm \frac{4\pi d}{\lambda} \left(1-\frac{1}{n^2}\sin^2 \theta \right) ^{1/2}\)
3
\(\rm \frac{4\pi d}{\lambda} \left(1-\frac{1}{n^2}\sin^2 \theta \right) ^{1/2}+\frac{\pi}{2}\)
4
\(\rm \frac{4\pi d}{\lambda} \left(1-\frac{1}{n^2}\sin^2 \theta \right) ^{1/2}+2\pi\)
5
Question Not Attempted

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation