BD and CE are the medians of Δ ABC, right angled at A. If CE = \(\frac{{5\sqrt {13} }}{2}\) cm, BC = 10 cm, then the length of BD is:

1
\(3\sqrt 5 \)  cm
2
\(3\sqrt 7 \) cm
3
\(\sqrt {13} \) cm
4
\(\frac{5}{2}\sqrt {7} \) cm

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