What is the value of 'a' for the given expression, if (x + y + z) ≠ 0?
\(\rm \frac{x}{3x+y+z}=\frac{y}{x+3y+z}=\frac{z}{x+y+3z}=2a\)
1
\(\frac{1}{15}\)
2
\(\frac{1}{10}\)
3
\(\frac{1}{5}\)
4
\(\frac{1}{2}\)
What is the value of 'a' for the given expression, if (x + y + z) ≠ 0?
\(\rm \frac{x}{3x+y+z}=\frac{y}{x+3y+z}=\frac{z}{x+y+3z}=2a\)